Proof that the slope of the k-value for exact compensation is one

k = log (initial density) / log (final density)
   = log (initial density / final density)
   = log (Before/After)
   = log (B/A)

Exact compensation: A = constant, slope b of k vs. B = 1

b = (k₂-k₁) / (log B₂ - log B₁)

   = (log B₂ - log A - (log B₁ - log A)) / (log B₂ - log B₁)

   = (log B₂ - log B₁) / (log B₂ - log B₁) = 1
 

QED
 

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